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Old 01-27-2012, 02:17 AM   #10901
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Got the new shocks on the daily, its insanely smooth over bumps.

550/350 springs.
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Old 01-27-2012, 10:08 AM   #10902
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Quote:
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Got the new shocks on the daily, its insanely smooth over bumps.

550/350 springs.
How do you complain about a van being to expensive and then go and drop 2k on suspension for your daily?
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Old 01-27-2012, 10:26 AM   #10903
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can you only adjust the ride height in .5" steps?
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Old 01-27-2012, 11:00 AM   #10904
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How do you complain about a van being to expensive and then go and drop 2k on suspension for your daily?
lol @ thinking I've paid full price for anything in my life. This was old-stock on the "get it out of here" price.

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can you only adjust the ride height in .5" steps?
You have probrem? It was the right price. The fronts have 1/2" grooves.
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Old 01-27-2012, 11:02 AM   #10905
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curious cat is all.
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Old 01-27-2012, 11:14 AM   #10906
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I should probably note that the rear shocks appear to be too short and I can't get the car higher than 4" so I have to come up with something, the spring is seated on the upper and lower perches at full droop.

BTW, full droop wheel position in the fender well is "lower" than factory Miata ride height, lol.
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Old 01-27-2012, 11:17 AM   #10907
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just needs longer springs.
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Old 01-27-2012, 11:20 AM   #10908
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just needs longer springs.
How will a longer spring increase ride height if the spring is snugged-up on the perches at full droop?
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Old 01-27-2012, 11:24 AM   #10909
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because the springs will be snugged up but longer.
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Old 01-27-2012, 11:25 AM   #10910
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because the springs will be snugged up but longer.
Won't that increase spring rate? The ride is insane-o smooth, but the springs are as firm as I want for the street. These shocks are so smooth over bump/RR tracks/speedbumps that I giggle.
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Old 01-27-2012, 11:26 AM   #10911
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Quote:
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Won't that increase spring rate?
think about that question for five minutes.
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Old 01-27-2012, 11:27 AM   #10912
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and furthermore, damn you for making me reply to this thread. I've been doing my best to not post in it for no good reason.
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Old 01-27-2012, 12:09 PM   #10913
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Quote:
Originally Posted by mgeoffriau View Post
So at work we have the "UPS Computer" which is really just an aging Dell desktop that UPS supplied when we set up our shipper account. [...] Today I decided to take on the project of preparing a few basic upgrades and then wiping the hard drive and reinstalling Windows XP.
Well, poop. I managed to get the RAM bumped up from 256 MB to 768 MB which helped quite a bit, but I couldn't find an AGP video card. I was sure I had one in one of my boxes of old computer stuff. Must have tossed that old Geforce 2 I had kicking around.

I did find my old Matrox Millenium II PCI video card, however. Who knows why I kept that and tossed the AGP card.

So, now the computer has...

Celeron 2.4 GHz
768 MB DDR SDRAM @ 333 MHz
Onboard Intel vidchip

...and it's not terrible with a clean install of XP.

Yay.
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Old 01-27-2012, 12:48 PM   #10914
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and furthermore, damn you for making me reply to this thread. I've been doing my best to not post in it for no good reason.
What does "linear" mean?
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Old 01-27-2012, 01:42 PM   #10915
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Quote:
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What does "linear" mean?
remember back in school when you learned the equation of a line?

y=m*x+b ?

it's a first order polynomial. x is raised to the 1 power. the graph of the equation is a straight line. linear.

That means that for whatever input you stick in for x, you'll get a value of y that is "m times" more than x.

or in the case of springs, for every inch you compress, you get "k times" (since the spring equation is F=k*x) that amount of force in pounds (assuming your rate "k" is in lbs/inch).

and for most springs with equal spacing between coils (which your ASTs appear to have) they are constant rate. or "linear springs". That means that no matter what length they are at, the spring rate never changes. so if they are unloaded and sitting on a desk, they are still the same rate as they are just before they are coil binding. at coil bind, the spring rate is effectively the spring rate of solid steel. or rounding up: infinite.


References:
http://en.wikipedia.org/wiki/Degree_of_a_polynomial
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Old 01-27-2012, 01:48 PM   #10916
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Quote:
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What does "linear" mean?
In this context, linearity describes the condition where the response produced by a system is always proportional to the input into the system, regardless of the magnitude of the input.

One example would be that applying 500 lbs of force to a spring causes it to compress by 1", applying 1,000 lbs causes it to compress by 2", applying 1,500 lbs for force causes it to compress by 3", etc. For every additional 500 lbs you add, the spring will compress by another inch.

In other words, the spring's effective rate does not change simply because it already partially compressed. It responds the same way (by compressing 1" per 500 lbs) regardless of how much input (weight) has already been applied to it, in much the same way that your mom's response to "input" does not vary throughout the course of the evening regardless of how much "input" she has already had.


edit: y8s beat me to it. And I got a chuckle out of "rounding up to infinity."
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Old 01-27-2012, 04:20 PM   #10917
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Old 01-27-2012, 04:42 PM   #10918
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i think that chart is incorrect.
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Old 01-27-2012, 04:49 PM   #10919
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i think that chart is incorrect.
you are correct.
the chart is incorrect.

the ordinate label should be "Force".
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Old 01-27-2012, 05:02 PM   #10920
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or if the "linear" was horizontal to the travel axis.
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