A lot of people keep asking me. So I'll lay it out very easily.
It should take you about 10-20 minutes, you just need 470ohm resistors to
make it happen.
On the top of the board:
The MS-II & MS-III daughter-boards require an alternative method to receive the second trigger. Therefore you must remove the jumpers for D1 and D2. You must also replace R12 with a 470ohm resistor. I used a 1/2watt to match the rating of the supplied resistor.
On the back of the board:
To continue the thought on the alternative method for the tach signal...Remove the jumper from XG2 a& XG1 and from Tachselect & OPOTIN. Now jump Tachselect to XG1.
The Main input is the same, but it's moved to JS10. The Daughter-board has an inline 1K resistor pressed onto the board, so you just need to keep the 470ohm pull-up from 5v. So run your main input from IAC1A to JS10 and then run a 470ohm resistor from 5v to JS10 as well.
Run another jumper from 5v to the top of the c30 pin. This provides a pullup from 5v through the 470ohm resistors you replaced on the front of the board for the 2nd trigger.
Now you must swap your ignition outputs because we all do it backwards on MS-I.
As far as hardware, that's it.