Dielectric constant of E85?
Anyone here know the dielectric constant of E85?
Gasoline is about 2 E100 is about 24.3 What I don't know is if gasoline mixed with ethanol changes it's properties. If not, then I guess it's just a math equation and I suk@math.com |
Originally Posted by emilio700
(Post 1012101)
Anyone here know the dielectric constant of E85?
Gasoline is about 2 E100 is about 24.3 What I don't know is if gasoline mixed with ethanol changes it's properties. If not, then I guess it's just a math equation and I suk@math.com ethanol has a dielectric constant of around 24 at 25 degrees Celsius while gasoline has a dielectric constant of around 2 at the same temperature. Read more: METHOD FOR TESTING AND CALIBRATING A CAPACITIVE FLEX FUEL SENSOR - Patent application I'd check the math, if you have the equipment, or an ability to farm it out to a chem lab. Check your local college chem dept? [more below] |
Use the baby bottle test to get known e85. Put it in sensor, record value.
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So, di-electric constant is: how easily the molecule becomes polarized, when exposed to an electrical field.
Water, obviously is highly polarize-able. IE: The fact that the the two molecules (compounds? It's been a while since chem class) are mixed with each other should not effect how the two react to an electrical field. So, we have a mixture of 15% gasoline, 85% ethanol. Thus, if he have 1 Liter of e85; we have 150ml of gasoline, and 850ml of ethanol, ASSuming there is no water (or other) contamination. 15% of your solution has a DC of 2, and the other 85% has one of 24. But, we have to go into moles, to get an accurate percentage. [more] |
D=m/v
density of gasoline is about .75 kg/l which is 750 grams/liter 750g/l = 750g of gasoline molecules per liter of "gas" 750g/X = 114/1 X = # of moles 6.5789 moles of gasoline. |
1 Attachment(s)
moles you say?
https://www.miataturbo.net/attachmen...ine=1368670983 |
Originally Posted by 2ndGearRubber
(Post 1012123)
So, di-electric constant is: how easily the molecule becomes polarized, when exposed to an electrical field.
Water, obviously is highly polarize-able. IE: The fact that the the two molecules (compounds? It's been a while since chem class) are mixed with each other should not effect how the two react to an electrical field. So, we have a mixture of 15% gasoline, 85% ethanol. Thus, if he have 1 Liter of e85; we have 150ml of gasoline, and 850ml of ethanol, ASSuming there is no water (or other) contamination. 15% of your solution has a DC of 2, and the other 85% has one of 24. But, we have to go into moles, to get an accurate percentage. [more] |
We do the same for E85.
D=M/V 801 g/l = 801g of Ethonal per liter of "ethonal" 801/X = 46/1 17.413 moles of ethonal |
So, within a liter of E85, we have 17.413 moles of ethonal, and 6.5789 moles of gasoline.
17.413 moles, have a DC of 24.3 6.5789 moles, have a DC of 2.0 Total moles of out solution is approx. 23.992 moles. per liter. (molarity, is actually the term, Mr. PSI ;) ) So: 17.413/23.992 = .726 or 72.6% is Ethonal, by mass 27.4% is gasoline, by mass. [Getting a shower, more to come] |
2 x .274 = .548
24 x .762 = 18.288 18.836 is the total DC of a solution of E85. As the link I posted earlier states, the likely hood of getting pure E85 is kinda low. Gotta be some water in it. (I was high as hell through all of AP Chem, use at your own risk) |
Originally Posted by 2ndGearRubber
(Post 1012140)
2 x .274 = .548
24 x .762 = 18.288 18.836 is the total DC of a solution of E85. As the link I posted earlier states, the likely hood of getting pure E85 is kinda low. Gotta be some water in it. (I was high as hell through all of AP Chem, use at your own risk) +1 |
Dielectric constants are given at a certain pressure and temperature, or at least that is my understanding. They don't behave in a linear fashion either. I believe in order to get an accurate answer you would need to test your material in the desired conditions.
What's your application that you have worries about? |
Could make a simple parallel plate capacitor to test it. Charge it with nothing in between, calculate charge on cap, remove battery, put dielectric in between measure voltage. Would need to put a thin layer of insulation around the plates just in case though. Capacitance for parallel plate is ϵ A/d and Charge = V C. Although this is too much work and science
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You measure capacitance with a capacitance meter.
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True but I do not think emillio has one which is why I suggested that
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