PAT!

iTrader: (1)

If I've replaced a solenoid with a resistance of ~13.5ohms with one that has a resistance of 23ohms is there any way that I can alter that 2nd value to match the first? I know that raising the resistance is easily done... Oh, its a 12v solenoid but not sure of the amps that it draws.

olderguy

iTrader: (19)

Why?

PAT!

iTrader: (1)

To avoid a check engine light... there are several reasons why "get a different solenoid with the correct ohm rating" isn't a viable solution.

neogenesis2004

iTrader: (12)

run a 33ohm resistor in parallel with it

PAT!

iTrader: (1)

So a 33ohm resistor in parallel with the 23ohm solenoid will give me a resistance value of ~13ohm? Does it matter which wire that it is on?

neogenesis2004

iTrader: (12)

it wont make my drawing look correct.....

|
|--------|
|xxxxxxx |
s xxxxx r
o xxxxx e
l xxxxxx s
| xxxxxxx |
|--------|
|
|

the x's are just supposed to take space.
that would make the total resistance 13.5ohms from the input to the output

Ben

iTrader: (33)

a 33 ohm load in parallel with a 22 ohm load combines to a net of 13.2 ohms

neogenesis2004

iTrader: (12)

exactly, I rounded Also he said 23 not 22. So (23*33)/(23+33) = 13.55

Ben

iTrader: (33)

Heh I wasn't checking your math, I was responding to Pat.

But good job on checking mine. :gay:

neogenesis2004

iTrader: (12)

Gotta keep you on your A game

PAT!

iTrader: (1)

Cool guys, I appreciate the help

neogenesis2004

iTrader: (12)

tell us if it works

PAT!

iTrader: (1)

So, the resistor would be bridged between the two wires correct?

neogenesis2004

iTrader: (12)

correct, between the "entrance" and the "exit". They should share the same feed and ground.

PAT!

iTrader: (1)

Awesome. I will let you know how it turns out...