Derivatives Of Log. Functions... HELP!!! Calculus II is a Bitch!
11-03-2007, 09:59 AM
#23
Think Calc is hard...just wait for thermo. Nothing better than a take home test with one problem that takes 40hrs to complete.
It's even better when your professor's English is about as clear as mud.
I will say it is all worth it in the end. A professional salaried job makes playing with cars and racing a little easier. Stick with it!
It's even better when your professor's English is about as clear as mud.
I will say it is all worth it in the end. A professional salaried job makes playing with cars and racing a little easier. Stick with it!
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11-03-2007, 11:46 AM
#26
I grdauated in May, my last math course was calc three sophomore year 
to be honest I have no idea. Calc was never that hard for me, the problem is you have teachers instead of teaching you the overall concept and then walking you through derivations for each case, they try to teach you "rules" for each type, ie chain rule or whatever. It really didn't click until i took a class after differential equations that I cant remember the name of.
But pat, get one of those calculators that does everything. I had a voyage 200, but while they wouldn't let me use it in test it allowed me to double check all my answers for hw
to be honest I have no idea. Calc was never that hard for me, the problem is you have teachers instead of teaching you the overall concept and then walking you through derivations for each case, they try to teach you "rules" for each type, ie chain rule or whatever. It really didn't click until i took a class after differential equations that I cant remember the name of. But pat, get one of those calculators that does everything. I had a voyage 200, but while they wouldn't let me use it in test it allowed me to double check all my answers for hw
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loki you my math hero 
11-03-2007, 01:19 PM
#30
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Perhaps a higher level Texas Instruments? I've never heard of a Voyage before.
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11-03-2007, 02:18 PM
#32
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Thanks Ben, that helps. Then you can simplify 2(cos/sin)x to 2cotx. That's the final answer in my notes, so that must be how to get to it.
Thanks everybody for all the help. This is the best turbochaged miata/Calculus help Forum in the world!!!
Thanks everybody for all the help. This is the best turbochaged miata/Calculus help Forum in the world!!!
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11-03-2007, 04:08 PM
#35
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Do any higer level calculators actually show the steps involved to solving the problem? Perhaps that's asking too much, but if I'm buying it to help me learn, that would be the deciding factor come time to buy one.
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11-03-2007, 07:07 PM
#38
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Problem: Y=ln(x^4(sin^2(x))) Find first derivative.
=(d/dx) ln(x^4(sin^2(x)))
=4lnx+ 2lnsin^2x
=(4/x)+2(1/sinx)cosx
=(4/x)+2cotx
^^that is your answer
I have the same book but I am in calc one, i hate differentiations
*EDIT* sorry i didnt realize you already had the answer
=(d/dx) ln(x^4(sin^2(x)))
=4lnx+ 2lnsin^2x
=(4/x)+2(1/sinx)cosx
=(4/x)+2cotx
^^that is your answer
I have the same book but I am in calc one, i hate differentiations
*EDIT* sorry i didnt realize you already had the answer
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