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Old 04-03-2007, 03:18 PM   #1
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Default Electrical help

If I've replaced a solenoid with a resistance of ~13.5ohms with one that has a resistance of 23ohms is there any way that I can alter that 2nd value to match the first? I know that raising the resistance is easily done... Oh, its a 12v solenoid but not sure of the amps that it draws.
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Old 04-03-2007, 04:25 PM   #2
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Why?
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Old 04-03-2007, 04:53 PM   #3
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To avoid a check engine light... there are several reasons why "get a different solenoid with the correct ohm rating" isn't a viable solution.
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Old 04-03-2007, 05:05 PM   #4
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run a 33ohm resistor in parallel with it
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Old 04-03-2007, 05:29 PM   #5
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So a 33ohm resistor in parallel with the 23ohm solenoid will give me a resistance value of ~13ohm? Does it matter which wire that it is on?
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Old 04-03-2007, 05:40 PM   #6
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it wont make my drawing look correct.....

|
|--------|
|xxxxxxx |
s xxxxx r
o xxxxx e
l xxxxxx s
| xxxxxxx |
|--------|
|
|

the x's are just supposed to take space.
that would make the total resistance 13.5ohms from the input to the output
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Old 04-03-2007, 05:46 PM   #7
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a 33 ohm load in parallel with a 22 ohm load combines to a net of 13.2 ohms
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Old 04-03-2007, 06:00 PM   #8
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exactly, I rounded Also he said 23 not 22. So (23*33)/(23+33) = 13.55
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Old 04-03-2007, 06:03 PM   #9
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Quote:
Originally Posted by neogenesis2004 View Post
exactly, I rounded Also he said 23 not 22. So (23*33)/(23+33) = 13.55
Heh I wasn't checking your math, I was responding to Pat.

But good job on checking mine. :gay:
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Old 04-03-2007, 06:10 PM   #10
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Gotta keep you on your A game
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Old 04-03-2007, 07:05 PM   #11
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Cool guys, I appreciate the help
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Old 04-03-2007, 07:09 PM   #12
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tell us if it works
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Old 04-03-2007, 07:10 PM   #13
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So, the resistor would be bridged between the two wires correct?
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Old 04-03-2007, 07:11 PM   #14
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correct, between the "entrance" and the "exit". They should share the same feed and ground.
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Old 04-03-2007, 08:10 PM   #15
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Awesome. I will let you know how it turns out...
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