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Old 06-09-2009, 10:50 PM   #1
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Default Actual data, advance vs. torque (MBT)

I found this graph on efi101.com

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X axis is timing advance, and Y axis is torque, plotted by a dyno that can communicate with the ECU.
The 3 curves are for 1500, 2000, and 2500 RPM, at WOT on an NA car.

Take the green curve, 2500 RPM. The (geometric) peak occurs at around 31. The torque is fairly constant from 31-33. MBT is 31.

However you can see that at 25-26, the car is only ~1.5 ft-lbs down from 31 (< 1%). That 4-5 of retard down from MBT is a lot less peak force pushing down on the rod (from cylinder pressure). Rods will see less compressive loading... even in the absence of detonation.


Now if only I could find that graph of cylinder pressure vs. time at different values of advance, to show the reduction in peak cylinder pressure.
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Old 06-10-2009, 12:46 AM   #2
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Wow, that's very interesting. I would love to see the graph of a boosted BP at higher rpms, and the point at which detonation started to come into play. I'm sure it would be a much steeper curve.
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Old 06-10-2009, 01:11 AM   #3
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Originally Posted by pdexta View Post
Wow, that's very interesting. I would love to see the graph of a boosted BP at higher rpms, and the point at which detonation started to come into play. I'm sure it would be a much steeper curve.
Power output would just go up and up till you hit detonation.


Now what I want to see is graps of 4k, 5k, 6k at around 23 kpa, that was I could tune for cruise timing lol.
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Old 06-10-2009, 09:39 AM   #4
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Quote:
Originally Posted by cardriverx View Post
Power output would just go up and up till you hit detonation.
Or until you achieved MBT. Don't laugh, it's possible.

But agreed, I'd really love to see this data for a much broader spread of RPM.
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Old 06-10-2009, 03:33 PM   #5
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At any RPM the general shape will be the same, at least in the absence of detonation.
Detonation, IIRC causes momentary dips in torque, at least I've seen it in RPM sweep dyno plots (knock sensor turned off).
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Old 07-01-2009, 04:45 PM   #6
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Here's a plot of cyl pressure vs timing (on the left)>

See that with more advance peak cylinder pressures rise.
Retarding timing so that torque is 1-2% down from MBT will reduce peak cylinder pressures, probability of knock, and stress on ring lands and rods.
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Actual data, advance vs. torque (MBT)-cyl-pressure-vs-timing-110829_6mg.jpg  
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Old 07-01-2009, 05:32 PM   #7
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Quote:
Originally Posted by cardriverx View Post
Power output would just go up and up till you hit detonation.
Sorry for the stupid question, but is that to imply that MBT typically occurs at the point that the motor begins to detonate? For some reason I was under the impression that power output would start to fall off before detonation occurs.
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Old 07-01-2009, 06:26 PM   #8
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It can go either way.
Depends on the motor, boost, temperature, octane.
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Old 07-01-2009, 08:46 PM   #9
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i saw the same results on the dyno with torque.
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Old 07-01-2009, 09:27 PM   #10
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Great thread.

I'm curious though.

Lets take 2 motors both FI'd both running the same fuel, boost intake temps etc.
Only thing different between the 2 motors would be the CR.

Lets say motor #1 is 10.5:1 CR, #2 is 9:1.

Obviously for the same amount of advance the higher compression motor will make more power and run more efficiently.

But if the boost means the higher compression motor can't meet MBT without det but motor #2 can how will this affect the power outputs?

What i'm asking is will the higher compression motor make just as much power even though we need to pull timing, or will the lower compression motor reaching MBT be THAT much more efficient?


To my limited understanding if your retarding the timing on a high compression motor then your starting your ignition before you've reached full squish.

But on the other hand if your running a lower compression motor the squish is not going to be as much anyways.

But what about the efficiency of the other 3 cycles?


Cheers
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Old 07-02-2009, 06:39 PM   #11
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Quote:
Originally Posted by eunos1800 View Post
But if the boost means the higher compression motor can't meet MBT without det but motor #2 can how will this affect the power outputs?

What i'm asking is will the higher compression motor make just as much power even though we need to pull timing, or will the lower compression motor reaching MBT be THAT much more efficient?
Retarding timing to prevent ping will typically make you lose more torque than what the higher c/r gains. The answer could be WI. 1 point of compression is worth 3-4% in thermal efficiency, (and may also affect VE). You can easily lose 5-10% in output if you have to retard lots and lots, not to mention your EGT's will spiral up.

Quote:
To my limited understanding if your retarding the timing on a high compression motor then your starting your ignition before you've reached full squish.
A better explanation is that somewhere in the chamber a portion of the intake charge may spontaneously combust before the flame front reaches it. Detonation can actually commence *after* the spakr of after TDC. The temps of the charge at TDC have a huge impact, which is why c/r and intake temps have a huge effect, and why a denser charge (e.g. FI), has lesser effect than c/r.
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Old 07-02-2009, 10:06 PM   #12
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Interesting stuff thanks.

That's what i love about engineering and motor tuning.
It's finding that ideal compromise.

Yep WI might well allow you to claw back that few degrees of timing, but then start injecting too much water and again you start to loose power.
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Old 07-02-2009, 10:59 PM   #13
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Jason, where on earth are you finding this wonderful data?
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Old 07-02-2009, 11:07 PM   #14
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Dunno man, where on earth do you find all the good stuff you post LOL

The last one was from Autospeed.com, found it while I was looking for a different article. Lots of little gems over there.
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Old 10-18-2009, 04:36 AM   #15
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sooo...does this mean you shouldn't have your spark advance past 26* to ease up on the rings?
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